Question
Find the value of: ${ }^{80} \mathrm{C}_2$

Answer

$
\begin{aligned}
&{ }^{80} \mathrm{C}_2=\frac{80 !}{2 !(80-2) !}=\frac{80 !}{2 ! 78 !} \\
&=\frac{80 \times 79 \times 78 !}{2 \times 78 !} \\
& \\
&=40 \times 79=3160
\end{aligned}
$

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