Question
Find the value of discriminant.
$\sqrt{2} x ^2+4 x +2 \sqrt{2}=0$
$\sqrt{2} x ^2+4 x +2 \sqrt{2}=0$
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Answer
$\sqrt{2} x ^2+4 x +2 \sqrt{2}=0 \text { compare with } ax ^2+ bx + c =0 $
$ \Rightarrow a =\sqrt{2}, b=4 \text { and } c =2 \sqrt{2} $
$\therefore b ^2-4 ac =4^2-4(\sqrt{2})(2 \sqrt{2}) $
$ =16-16 $
$ =0$
$ \Rightarrow a =\sqrt{2}, b=4 \text { and } c =2 \sqrt{2} $
$\therefore b ^2-4 ac =4^2-4(\sqrt{2})(2 \sqrt{2}) $
$ =16-16 $
$ =0$
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