Question
Find:$10^{th}$^ term of the A.P. $-40, -15, 10, 35, .....$

Answer

Given A.P. is
$-40,-15,10,35, \ldots .$
First term (a) = -40
Common difference $( d )=$ second term - first term
$=40-15$
$=25$
$n^{\text {th }}$ term of an A.P. $a_n=a+(n-1) d$
$10^{\text {th }}$ term of A.P. $a_{10}=-40+(10-1) 25$
$=-40+9 \times 25$
$=-40+225$
$=185$

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