Question
Find the value of :
$\frac{3}{13}÷\left(\frac{-4}{65}\right)$

Answer

We have, $\frac{3}{13} \div\left(\frac{-4}{65}\right)=\frac{3}{13} \times$ Reciprocal of $\left(\frac{-4}{65}\right)$
$=\frac{3}{13} \times\left(\frac{65}{-4}\right)=\frac{3 \times 65}{13 \times(-4)}$
$=\frac{3 \times 5}{(-4)}=\frac{15}{-4}=\frac{-15}{4}$

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