Question
Find the value of :
$\frac{-4}{5} \div(-3)$
$\frac{-4}{5} \div(-3)$
✓
Answer
We have, $\frac{-4}{5}\div(-3)=\frac{-4}{5}\div\frac{(-3)}{1}=\frac{-4}{5}$x Reciprocal of(-3)
$=\frac{-4}{5} \times \frac{1}{(-3)}=\frac{(-4) \times 1}{5 \times(-3)}=\frac{-4}{-15}=\frac{4}{15}$
$=\frac{-4}{5} \times \frac{1}{(-3)}=\frac{(-4) \times 1}{5 \times(-3)}=\frac{-4}{-15}=\frac{4}{15}$
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