Question
Find the value of $\int b^{2 x} d b$ :

Answer

$\int b^{2 x} d b$
Here we need to integrate with respect to $x$
$
\therefore \int b^{2 x} d b=\frac{b^{2 x+1}}{2 x+1}+C \quad\left(\because \int b^n d b=\frac{b^{n+1}}{n+1}+C\right)
$

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