Question
Find the value of $\left[2^{-1} \times 3^{-1}\right]^{-1}$.
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Answer
$\begin{array}{l}\because 2^{-1} \times 3^{-1}=\frac{1}{2} \times \frac{1}{3}=\frac{1}{6} \\ \therefore\left[2^{-1} \times 3^{-1}\right]^{-1}=\left[\frac{1}{6}\right]^{-1}=6\end{array}$
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