Question
find the value of $n$. $\frac{6^\text{n}}{6^{-2}}=6^3$

Answer

Given,
$\frac{6^\text{n}}{6^{-2}}=6^3$
Using law of exponents, $\frac{6^\text{n}}{6^{-2}}=6^3$ [$\because$ a is non-zero integer]
$\Rightarrow6^{\text{n}+1}=6^3$ [$\because$ $a^m÷ a^n= a^{m-n}] $
On comparing both sides, we get
$n + 2 = 3$
$\Rightarrow n = 1$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free