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Redox Reactions — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryRedox Reactions1 Mark
Question
Find the value of n in:
$4\text{MnO}^-_4+8\text{H}^++\text{ne}^-\xrightarrow{\ \ \ \ \ \ }\text{Mn}^{2+}+4\text{H}_2\text{O}$
✓

Answer

$\text{MnO}^-_4+8\text{H}^++\text{ne}^-\xrightarrow{\ \ \ \ \ }\text{Mn}^{2+}+4\text{H}_2\text{O}$
$-1+8+n=+2$
$-1-2+8+n=0$
$n=-5 \text { or } 5 e^{-}$
 

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