Question
Find the value of $\sqrt{ }-3 \times \sqrt{ }-6$.

Answer

$\sqrt{ -3} \times \sqrt{ }-6=\sqrt{ 3} \times \sqrt{ -1}+\sqrt{ 6} \times \sqrt{ -1}$
$=\sqrt{ 3 i} \times \sqrt{ 6 i}$
$=\sqrt{ 18} i^2$
$=-3 \sqrt{ 2} \ldots \ldots\left[\because i^2=-1\right]$

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