Question
Find the value of the angle in the given figure:
✓
Answer
In the figure, $\angle \mathrm{A}+\angle \mathrm{B}+\angle \mathrm{C}=180^{\circ}$.....(Sum of angles of a triangle)
$ \begin{aligned} & \Rightarrow x^{\circ}+2 x^{\circ}+2 x^{\circ}=180^{\circ} \\ & \Rightarrow 5 x^{\circ}=180^{\circ} \\ & \Rightarrow x^{\circ}=\frac{180^{\circ}}{5}=36^{\circ} \end{aligned} $
$\therefore \angle \mathrm{A}=\mathrm{x}^{\circ}=36^{\circ}$
$ \angle B=2 x^{\circ}=2 \times 36^{\circ}=72^{\circ} $
and $\angle \mathrm{C}=2 \mathrm{x}^{\circ}=2 \times 36^{\circ}=72^{\circ}$
$ \begin{aligned} & \Rightarrow x^{\circ}+2 x^{\circ}+2 x^{\circ}=180^{\circ} \\ & \Rightarrow 5 x^{\circ}=180^{\circ} \\ & \Rightarrow x^{\circ}=\frac{180^{\circ}}{5}=36^{\circ} \end{aligned} $
$\therefore \angle \mathrm{A}=\mathrm{x}^{\circ}=36^{\circ}$
$ \angle B=2 x^{\circ}=2 \times 36^{\circ}=72^{\circ} $
and $\angle \mathrm{C}=2 \mathrm{x}^{\circ}=2 \times 36^{\circ}=72^{\circ}$
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