- Find the value of the phase difference between the current and the voltage in the series LCR circuit shown below. Which one leads in phase: current or voltage?
- Without making any other change, find the value of the additional capacitor $C_1,$ to be connected in parallel with the capacitor C, in order to make the power factor of the circuit unity.
CBSE DELHI - SET 2 2017
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- $X_L=\omega_L=(1000\times100\times10^{-3})\Omega=100\Omega$
Phase angle
$\tan\Phi=\frac{X_L-X_C}{R}$
$\tan\Phi=-\frac{\pi}{4}$
As $X_C>X_L$ (phase angle is negative), hence current leads voltage
- To make power factor unity
$\frac{1}{WC'}=100$
$C'=10\mu\text{F}$
$C'=C+C_1$
$10=2+C_1$
$C_1=8\mu\text{F}$
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