Algebraic Expressions and Identities — MATHS STD 8 — Question
Gujarat BoardEnglish MediumSTD 8MATHSAlgebraic Expressions and Identities3 Marks
Question
Find the value of $x$, if:
$ 4x = (52)^2- (48)^2$
✓
Answer
Let us consider the following equation:
$4x = (52)^2- (48)^2$
Using the identity $(a + b) (a - b) = a^2- b^2$
we get:
$4x = (52)^2- (48)^2$
$4x= (52 + 48)(52 - 48)$
$4x= 100 \times 4 = 400$
$\Rightarrow 4x = 400$
$\Rightarrow x = 100$ (Dividing both sides by $4)$
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