Question
Find the value $'x\ ',$ if:
✓
Answer
$\text{BEDC}$ is a rectangle.
$\Rightarrow BE$
$ = DC$
$ =60 \sqrt{3}\ m$
In right $\triangle A E B$,
$\tan 30^{\circ}=\frac{ AE }{ BE }$
$ \Rightarrow \frac{1}{\sqrt{3}}=\frac{ AE }{60 \sqrt{3}}$
$ \Rightarrow AE =60\ m$
Now,
$x=A D=A E+E D$
$ =60+15$
$ =75\ m .$
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