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Trigonometry — Maths STD 9 — Question

Maharashtra BoardEnglish MediumSTD 9MathsTrigonometry2 Marks
Question
Find the values of : $5 \sin 30^{\circ}+3 \tan 45^{\circ}$
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Answer

$ \sin 30^{\circ}=\frac{1}{2} \text { and } \tan 45^{\circ}=1$
$5 \sin 30^{\circ}+3 \tan 45^{\circ}=5\left(\frac{1}{2}\right)+3(1)$
$=\frac{5}{2}+3$
$=\frac{5+6}{2}$
$\therefore \quad 5 \sin 30^{\circ}+3 \tan 4 5 =\frac{11}{2}$

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