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Trigonometry – II — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsTrigonometry – II1 Mark
Question
Find the values of : cot 225°
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Answer

$\begin{aligned} \cot 225^{\circ} & =\frac{1}{\tan 225^{\circ}}=\frac{1}{\tan \left(180^{\circ}+45^{\circ}\right)} \\ & =\frac{1}{\left(\frac{\tan 180^{\circ}+\tan 45^{\circ}}{1-\tan 180^{\circ} \tan 45^{\circ}}\right)} \\ & =\frac{1}{\left(\frac{0+1}{1-0(1)}\right)} \\ & =\frac{1}{\left(\frac{1}{1}\right)} \\ & =1\end{aligned}$

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