Write the area of the circle passing through (-2, 6) and having i… - Vidyadip

Question

Write the area of the circle passing through (-2, 6) and having its centre at (1, 2).

✓

Answer

Radius of circle = Distance between centre (1, 2) and (-2, 6)
$=\sqrt{(1+2)^2+(2-6)^2}$
$=\sqrt{9+16}$
$=5$
Area of the circle = $25\pi$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "Solve the following Question.(1 Marks)" from The Circle→The Circle — all question types→Maths STD 11 Science question papers→Maharashtra Board STD 11 Science question papers→Maharashtra Board question paper generator→

Similar questions

Evaluate the following limits:

$\lim _{x \rightarrow 3}\left[\frac{\sqrt{2 x+6}}{x}\right]$

Determine the contrapositive of the following statements:
If x is less than zero, then x is not positive.

If $3\tan(\text{x}-15^{\circ})=\tan(\text{x}+15^{\circ}),0<\text{x}<90^{\circ},$ find x.

Find the degree measure corresponding to the following radian measures: $(\text{Use}\ \pi=\frac{22}{7})$
$\frac{9\pi}{5}$

Write the solution set of $x$ satisfying the inequation $(x^2 - 2x + 1) (x - 4) > 0$.

R : {1, 2, 3} → {1, 2, 3} given by R = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 3)}. Check if R is
symmetric

The given following sets are finite & in which of it infinite in if?
Set of letters of the English Alphabets;

Check whether the following sequences are G.P. If so, write $t_n$.
7, 14, 21, 28, ……

Find the nth term and hence find the 8th term of the following HPs.

$\frac{1}{4}, \frac{1}{6}, \frac{1}{8}, \frac{1}{10}, \ldots$

If $\text{x}\cos\theta=\text{y}\cos\Big(\theta+\frac{2\pi}{3}\Big)=\text{z}\Big(\theta+\frac{4\pi}{3}\Big),$ then write the value of $\frac{1}{\text{x}}+\frac{1}{\text{y}}+\frac{1}{\text{z}}.$