Find the values of : sec (-855°) - Vidyadip

Question

Find the values of : sec (-855°)

✓

Answer

\begin{aligned}
& \sec \left(-855^{\circ}\right)=\sec \left(855^{\circ}\right) \\
& =\sec \left(720^{\circ}+135^{\circ}\right) \\
& =\sec \left(2 \times 360^{\circ}+135^{\circ}\right)=\sec 135^{\circ} \\
& =\sec \left(90^{\circ}+45^{\circ}\right) \\
& =-\operatorname{cosec} 45^{\circ} \\
& =-\sqrt{2} \\
\end{aligned}

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "Solve the following Question.(1 Marks)" from Trigonometry – II→Trigonometry – II — all question types→Maths STD 11 Science question papers→Maharashtra Board STD 11 Science question papers→Maharashtra Board question paper generator→

Similar questions

Describe the following sets in Roster form:
{x ∈ N : x is a prime number, 10 < x < 20};

Write the values of the square root of -i.

From the sets given below, select equal sets and equivalent sets.
A = {0, a},
B = {1, 2, 3, 4},
C = {4, 8, 12},
D = {3, 1, 2, 4},
E = {1, 0},
F = {8, 4, 12},
G = {1, 5, 7, 11},
H = {a, b}.

If A and B are two sets such that n(A) = 115, n(B) = 326 and n(A - B) = 47, then write $\text{n(A}\cup\text{B)}.$

If $\text{R}=\{(\text{x, y}):\text{x},\text{ y}\in\text{Z},\text{ x}^2+\text{y}^2\leq4\}$ is a relation defined on the set Z of integers, then write domain of R.

Find the values of : $\cos 1140^{\circ}$

The equations of two sides of a square are 5x - 12y - 65 = 0 and 5x - 12y + 26 = 0. Find the area of the square.

If n is any positive integer, write the value of $\frac{\text{i}^{4\text{n}+1}-\text{i}^{4\text{n}-1}}{2}.$

Find the radian measure corresponding to the following degree measures:
35°

Which of the following cannot be valid assignment of probability for elements or outcomes of sample space $s = W_1, W_2,W_{3,} W_4, W_5, W_6, W_7.$

Elementary events:	$W_1$	$W_2$	$W_3$	$W_4$	$W_5$	$W_6$	$W_7$
	$0.1$	$0.01$	$0.05$	$0.03$	$0.01$	$0.2$	$0.6$