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Trigonometry – II — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsTrigonometry – II1 Mark
Question
Find the values of : sin 495°
✓

Answer

$
\begin{aligned}
& \sin 495^{\circ}=\sin \left(360^{\circ}+135^{\circ}\right) \\
& =\sin \left(135^{\circ}\right) \\
& =\sin \left(90^{\circ}+45^{\circ}\right) \\
& =\cos 45^{\circ} \\
& =\frac{1}{\sqrt{2}} \\
\end{aligned}
$

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