Question
Find the volume, curved surface area and total surface area of the cylinders whose dimensions are:
Radius of the base $= 7\ cm$ and height $= 50\ cm.$
Radius of the base $= 7\ cm$ and height $= 50\ cm.$
✓
Answer
Radius of the base of the cylinder $(r) = 7\ cm.$
Height $(h) = 50\ cm.$
$a. \therefore$ Volume $=\pi\text{r}^2\text{h}$
$=\frac{22}{7}\times(7)^2\times50\text{cm}^3$
$=\frac{22}{7}\times7\times7\times50\text{cm}^3$
$=7700\text{cm}^3$
$b.$ Lateral surface area $=2\pi\text{rh}$
$=2\times\frac{22}{7}\times7\times50$
$=2200\text{cm}^2$
$c.$ Total surface area $=2\pi\text{r}(\text{h}+\text{r})$
$=2\times\frac{22}{7}\times7(50+7)\text{cm}^2$
$=44\times57$
$=2508\text{cm}^2$
Height $(h) = 50\ cm.$
$a. \therefore$ Volume $=\pi\text{r}^2\text{h}$
$=\frac{22}{7}\times(7)^2\times50\text{cm}^3$
$=\frac{22}{7}\times7\times7\times50\text{cm}^3$
$=7700\text{cm}^3$
$b.$ Lateral surface area $=2\pi\text{rh}$
$=2\times\frac{22}{7}\times7\times50$
$=2200\text{cm}^2$
$c.$ Total surface area $=2\pi\text{r}(\text{h}+\text{r})$
$=2\times\frac{22}{7}\times7(50+7)\text{cm}^2$
$=44\times57$
$=2508\text{cm}^2$
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