Question
Find the volume, lateral surface area and the total surface area of the cuboid whose dimensions are:
Length $= 48\ cm$, breadth $= 6\ dm$ and height $= 1\ m.$
Length $= 48\ cm$, breadth $= 6\ dm$ and height $= 1\ m.$
✓
Answer
Length of cuboid $(l) = 48\ cm.$
Breadth $(b) = 6dm = 60\ cm.$
Height $(h) = 1m = 100\ cm.$
$a.$ Volume $= lbh = 48 \times 60 \times 100$
$= 288000\ cm^3$
$b.$ Lateral surface area $= 2(l + b) \times h$
$=2(48+60) \times 100 \ cm^2 $
$=2 \times 108 \times 100$
$=21600 \ cm^2$
$c.$ Total surface area $= 2[lb + bh + hl]$
$=2[48 \times 60+60 \times 100+100 \times 48] \ cm ^2 $
$ =2[2880+6000+4800] \ cm ^2$
$ =2[13680]$
$=27360 \ cm^2$
Breadth $(b) = 6dm = 60\ cm.$
Height $(h) = 1m = 100\ cm.$
$a.$ Volume $= lbh = 48 \times 60 \times 100$
$= 288000\ cm^3$
$b.$ Lateral surface area $= 2(l + b) \times h$
$=2(48+60) \times 100 \ cm^2 $
$=2 \times 108 \times 100$
$=21600 \ cm^2$
$c.$ Total surface area $= 2[lb + bh + hl]$
$=2[48 \times 60+60 \times 100+100 \times 48] \ cm ^2 $
$ =2[2880+6000+4800] \ cm ^2$
$ =2[13680]$
$=27360 \ cm^2$
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