Question
Making use of the cube root table, find the cube root $833$

Answer

We have:$830 < 833 < 840$
$\Rightarrow\sqrt[3]{830}<\sqrt[3]{833}<\sqrt[3]{840}$
From the cube root table, we have:
$\sqrt[3]{830}=9.398$ and $\sqrt[3]{840}=9.435$
For the difference $(840 - 830),$ i.e., $10$, the difference in values
$= 9.435 - 9.398 = 0.037$
$\therefore$ For the difference of $(833 - 830)$, i.e., $3$, the difference in values
$=\frac{0.037}{10}\times3=0.0111=0.011$ (upto three decimal places)
$\therefore\sqrt[3]{833}$
$=9.398+0.011$
$=9.409$

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