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Determinants — MATHS STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 ScienceMATHSDeterminants2 Marks
Question
Find values of $x$ for which $\left|\begin{array}{ll}3 & x \\ x & 1\end{array}\right|=\left|\begin{array}{ll}3 & 2 \\ 4 & 1\end{array}\right|$.
✓

Answer

${\left( {3 - x} \right)^2} = 3 - 8$

$3 - {x^2} = 3 - 8$

$ - {x^2} = - 8$

$x = \pm \sqrt 8 $

$x = \pm 2\sqrt 2 $

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