Question
Find whether 1156 and 2800 are perfect squares using prime factorisation.

Answer

(i) $1156=(2 \times 2) \times(17 \times 17)$
$\begin{array}{l}=2^2 \times 17^2 \\ =(2 \times 17)^2 \\ =(34)^2 \\ \therefore \sqrt{ } 1156=34\end{array}$
(ii) $2800=(2 \times 2) \times(2 \times 2) \times(5 \times 5) \times 7$
$=2^2 \times 2^2 \times 5^2 \times 7$
Since the factors cannot be paired
$\therefore 2800$ is not a perfect square.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free