Question
Find whether the given equation have x = 2, y = 1 as a solution:x + y + 4 = 0.
✓
Answer
For x = 2, y = 1
x + y + 4 = 0
L.H.S. = x + y + 4
= 2 + 1 + 4 = 7
$\neq$ R.H.S
$\therefore x=2, y=1$ is not a solution of $x+y+4=0$.
x + y + 4 = 0
L.H.S. = x + y + 4
= 2 + 1 + 4 = 7
$\neq$ R.H.S
$\therefore x=2, y=1$ is not a solution of $x+y+4=0$.
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