Question
Find x. $\frac{-6^\text{x-7}{}}{7}=1$
✓
Answer
We have, $\Big(-\frac{6{}}{7}\Big)^\text{x-7}=1
$Using law of exponents, $x^0= 1[\because$ a is non-zero integer$]$
Then, $\Big(-\frac{6{}}{7}\Big)^\text{x-7}=1$
it is possible only, if $x = 7$
So, $\Big(\frac{-6^\text{}{}}{7}\Big)^{7-7}=1$
$\Rightarrow \ \Big(-\frac{6^\text{}{}}{7}\Big)^0=1$ $[\because\text{a}^0=1]$
Hence, $\text{x}=7$
$Using law of exponents, $x^0= 1[\because$ a is non-zero integer$]$
Then, $\Big(-\frac{6{}}{7}\Big)^\text{x-7}=1$
it is possible only, if $x = 7$
So, $\Big(\frac{-6^\text{}{}}{7}\Big)^{7-7}=1$
$\Rightarrow \ \Big(-\frac{6^\text{}{}}{7}\Big)^0=1$ $[\because\text{a}^0=1]$
Hence, $\text{x}=7$
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