Question
Find $x$, if $g(x)=0$ where
$g(x)=6 x^2+x-2$

Answer

$g(x)=6 x^2+x-2$
$g(x)=0$
$\therefore 6 x^2+x-2=0$
$\therefore(2 x-1)(3 x+2)=0$
$\therefore 2 x-1=0 \text { or } 3 x+2=0$
$\therefore x=\frac{1}{2} \text { or } x=\frac{-2}{3}$

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