Question
Find x in the following. $\frac{1}{4!}+\frac{1}{5!}=\frac{\text{x}}{6!}$
✓
Answer
We have, $\frac{1}{4!}+\frac{1}{5!}=\frac{\text{x}}{6!}$ $\Rightarrow\frac{1}{4!}+\frac{1}{4\times5!}=\frac{\text{x}}{6\times5\times4!}$ $\Rightarrow4!\times\bigg[\frac{1}{4!}+\frac{1}{5\times4!}\bigg]=\frac{\text{x}}{30}$ $\Rightarrow1+\frac{1}{58}=\frac{\text{x}}{30}$ $\Rightarrow\frac{6}{5}=\frac{\text{x}}{30}$ $\Rightarrow\frac{\text{x}}{30}=\frac{6}{5}$ $\Rightarrow\text{x}=\frac{6\times30}{5}$ $\Rightarrow6\times6$ $\Rightarrow\text{x}= 36$ Hence, $\text{x}= 36$
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