Question
Find $x$ in the following when$: \log _4 0.0625 = x$
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Answer
$\log _4 0.0625 = x$
$\Rightarrow 0.0625 = 4^x$
$\Rightarrow 4^x = 4^{-2}$
$\therefore x = -2.$
$\Rightarrow 0.0625 = 4^x$
$\Rightarrow 4^x = 4^{-2}$
$\therefore x = -2.$
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