Question
Find $x$, such that: $\frac{3}{7}=\frac{\mathrm{x}}{-35}$
✓
Answer
$\begin{aligned} & \frac{7}{-4}=\frac{x}{8} \\ & \Rightarrow \frac{3 \times-5}{7 \times-5}=\frac{\mathrm{x}}{-35} \\ & \Rightarrow \frac{-15}{-35}=\frac{\mathrm{x}}{-35} \\ & \Rightarrow x=-15\end{aligned}$
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