Question 13 Marks
The product of two rational numbers is 24 . If one of them is $-\frac{36}{11}$, find the other.
AnswerProduct of two numbers $=24$
$ \begin{aligned} & \text { One number }=\frac{-36}{11} \\ & \therefore \text { Second number }=24 \div \frac{-36}{11} \\ & =24 \times \frac{-11}{36} \\ & =2 \times \frac{-11}{3}=\frac{-22}{3} \end{aligned} $
View full question & answer→Question 23 Marks
What rational number should be subtracted from $-\frac{5}{12}$ to get $\frac{5}{24}$.
AnswerThe required number $=\frac{-5}{12}-\frac{5}{24}$
$ =\frac{-5 \times 2}{12 \times 2}-\frac{5}{24} $
( $\because$ LCM of 12 and 24 is 24$)$
$ \begin{aligned} & =\frac{-10}{24}-\frac{5}{24} \\ & =\frac{-10-5}{24} \\ & =\frac{-15}{24} \\ & =\frac{-5}{8} \end{aligned} $
View full question & answer→Question 33 Marks
What rational number should be added to $\frac{-3}{5}$ to get $2 ?$
AnswerThe required number $=2-\left(\frac{-3}{5}\right)$
$ =2+\frac{3}{5} $
$ =\frac{2 \times 5}{1 \times 5}+\frac{3 \times 1}{5 \times 1} $
$ =\frac{10+3}{5}=\frac{13}{5}=2 \frac{3}{5} $
View full question & answer→Question 43 Marks
The sum of two rational numbers is -5 . If one of them is $\frac{-52}{25}$, find the other.
AnswerSum of two numbers $=-5$
One number $=\frac{-52}{25}$
Second number $=-5-\left(\frac{-52}{25}\right)$
$ =\frac{-5 \times 25}{1 \times 25}+\frac{52 \times 1}{25 \times 1} $
$ =\frac{-125+52}{25}=\frac{-73}{25} $
$\therefore$ Second number $=\frac{-73}{25}$
View full question & answer→Question 53 Marks
The cost of 11 pens is ₹ $24 \frac{3}{4}$. Find the cost of one pen
AnswerThe cost of 11 pens is ₹ $24 \frac{3}{4}$.
One cost of a pen is calculated as,
$ \begin{aligned} & \text { cost }=24 \frac{3}{4} \div 11 \\ & =\frac{99}{4} \div \frac{11}{1} \\ & =\frac{99}{4} \times \frac{1}{11} \\ & =\frac{99 \times 1}{4 \times 11} \\ & =\frac{9}{4} \\ & =2 \frac{1}{4} \end{aligned} $
Therefore, the cost of one pen is ₹ $2 \frac{1}{4}$.
View full question & answer→Question 63 Marks
Divide: 35 by $\frac{-7}{9}$
Answer35 by $\frac{-7}{9}$
$ =35 \div \frac{-7}{9} \Rightarrow 35 \times \frac{9}{-7} $
$ =5 \times \frac{9}{-1} $
$ =\frac{5 \times 9}{-1}=\frac{45}{-1}=-45 $
View full question & answer→Question 73 Marks
Divide: $\frac{-22}{9}$ by $\frac{11}{18}$
Answer
$\begin{aligned} & \frac{-22}{9} \text { by } \frac{11}{18} \\ & =\frac{-22}{9} \div \frac{11}{18}=\frac{-22}{9} \times \frac{18}{11} \\ & =\frac{-2}{1} \times \frac{2}{1} \\ & =\frac{-2 \times 2}{1 \times 1}=\frac{-4}{1}=-4\end{aligned}$
View full question & answer→Question 83 Marks
Divide: -7 by $\frac{-14}{5}$
Answer
$\begin{aligned} & -7 \text { by } \frac{-14}{5} \\ & =-7 \div \frac{-14}{5} \\ & \Rightarrow-7 \times \frac{5}{-14} \Rightarrow 1 \times \frac{5}{2} \\ & =\frac{1 \times 5}{2}=\frac{5}{2}=2 \frac{1}{2}\end{aligned}$
View full question & answer→Question 93 Marks
Divide: $\frac{16}{-5}$ by $\frac{-8}{7}$
Answer
$\begin{aligned} & \frac{16}{-5} \text { by } \frac{-8}{7} \\ & =\frac{16}{-5} \div \frac{-8}{7} \Rightarrow \frac{16}{-5} \times \frac{7}{-8} \\ & =\frac{2}{-5} \times \frac{7}{-1} \\ & =\frac{2 \times 7}{-5 \times(-1)}=\frac{14}{5}=2 \frac{4}{5}\end{aligned}$
View full question & answer→Question 103 Marks
Evaluate: $\left(\frac{-35}{39} \times \frac{-13}{7}\right)-\left(\frac{7}{90} \times \frac{-18}{14}\right)$
Answer
$\begin{aligned} & \left(\frac{-35}{39} \times \frac{-13}{7}\right)-\left(\frac{7}{90} \times \frac{-18}{14}\right) \\ & =\frac{(-5) \times(-1)}{3 \times 1}-\left(\frac{1 \times(-1)}{5 \times 2}\right) \\ & =\frac{5}{3}-\left(-\frac{1}{10}\right) \\ & =\frac{5 \times 10}{3 \times 10}+\frac{1}{10 \times 3} \\ & =\frac{50+3}{30}=\frac{53}{30}=1 \frac{23}{30}\end{aligned}$
View full question & answer→Question 113 Marks
Evaluate: $\left(\frac{-5}{9} \times \frac{6}{-25}\right)+\left(\frac{24}{21} \times \frac{7}{8}\right)$
Answer
$\begin{aligned} & \left(\frac{-5}{9} \times \frac{6}{-25}\right)+\left(\frac{24}{21} \times \frac{7}{8}\right) \\ & =\left(\frac{5}{9} \times \frac{6}{25}\right)+\left(\frac{24}{21} \times \frac{7}{8}\right) \\ & =\frac{2}{3 \times 5}+1=\frac{2}{15}+1 \\ & =\frac{2+15}{15}=\frac{17}{15}=1 \frac{2}{15}\end{aligned}$
View full question & answer→Question 123 Marks
Evaluate: $\left(\frac{7}{8} \times \frac{8}{7}\right)+\left(\frac{-5}{9}\right) \times\left(\frac{6}{-25}\right)$
Answer
$\begin{aligned} & \left(\frac{7}{8} \times \frac{8}{7}\right)+\left(\frac{-5}{9}\right) \times\left(\frac{6}{-25}\right) \\ & =\left(\frac{7}{8} \times \frac{8}{7}\right)+\left(\frac{-5}{9} \times \frac{6}{-25}\right) \\ & =\frac{1}{1}+\frac{1 \times 2}{3 \times 5}=\frac{1}{1}+\frac{2}{15} \\ & =\frac{15+2}{15}=\frac{17}{15}=1 \frac{2}{15}\end{aligned}$
View full question & answer→Question 133 Marks
Evaluate: $2 \frac{14}{25} \times\left(\frac{-5}{16}\right)$
Answer
$\begin{aligned} & 2 \frac{14}{25} \times\left(\frac{-5}{16}\right) \\ & =\frac{2 \times 25+14}{25}
\times\left(\frac{-5}{16}\right)\end{aligned}$
$=\frac{64}{25} \times\left(\frac{-5}{16}\right)$
$=\frac{64 \times(-5)}{25 \times 16}=\frac{4 \times(-1)}{5 \times 1}=-\frac{4}{5}$
View full question & answer→Question 143 Marks
Evaluate: $3 \frac{1}{8} \times\left(-2 \frac{2}{5}\right)$
Answer
$\begin{aligned} & 3 \frac{1}{8} \times\left(-2 \frac{2}{5}\right) \\ & =\frac{3 \times 8+1}{8} \times\left(-\frac{2 \times 5+2}{5}\right) \\ & =\frac{25}{8} \times\left(-\frac{12}{5}\right)=\frac{25 \times(-12)}{8 \times 5} \\ & =\frac{5 \times(-3)}{2 \times 1}=\frac{-15}{2}\end{aligned}$
View full question & answer→Question 153 Marks
Seven equal pieces are made out of a rope 5 of $21 \frac{5}{7} \mathrm{~m}$. Find the length of each piece.
AnswerLength of 7 pieces of rope $=21 \frac{5}{7} \mathrm{~m}$
$ =\frac{21 \times 7+5}{7}=\frac{152}{7} $
Length of each piece $=\frac{152}{7} \div 7$
$ =\frac{152}{7} \times \frac{1}{7}=\frac{152}{49}=3 \frac{5}{49} \mathrm{~m} $
View full question & answer→Question 163 Marks
Evaluate: $\left(\frac{32}{15}+\frac{8}{5}\right) \div\left(\frac{32}{15}-\frac{8}{5}\right)$
Answer
$\begin{aligned} & \left(\frac{32}{15}+\frac{8}{5}\right) \div\left(\frac{32}{15}-\frac{8}{5}\right) \\ & \left(\frac{32 \times 1}{15 \times 1}+\frac{8 \times 3}{5 \times 3}\right) \div\left(\frac{32 \times 1}{15 \times 1}-\frac{8 \times 1}{5 \times 1}\right) \\ & (\because \text { L.C.M. of } 15,5=15) \\ & =\left(\frac{32+24}{15}\right) \div\left(\frac{32-24}{15}\right) \\ & =\frac{56}{15} \div \frac{8}{15} \Rightarrow \frac{56}{15} \times \frac{15}{8}=7\end{aligned}$
View full question & answer→Question 173 Marks
The sum of two rational numbers is -4 . If one of them is $\frac{-13}{12}$, fine the other.
Answer$\because$ Sum of two rational number $=-4$
and one of them $=-\frac{13}{12}$
$\therefore$ The other rational number $=-4-\left(-\frac{13}{12}\right)$
$=-4+\frac{13}{12}$
$=\frac{-4 \times 12+13}{12}$
$=\frac{-48+13}{12}=\frac{-35}{12}$
View full question & answer→Question 183 Marks
The sum of two rational numbers is $\frac{-7}{12}$. If one of them is $\frac{13}{24}$, fine the other.
Answer$\because$ Sum of two rational number $=\frac{-7}{12}$
and one of them $=\frac{13}{24}$
$\therefore$ The other rational number $=\frac{-7}{12}-\frac{13}{24}$
$=\frac{-7 \times 2}{12 \times 2}-\frac{13}{24}$
$=\frac{-14}{24}-\frac{13}{24}$
$=\frac{-14-13}{24}$
$=\frac{-27}{24}$
$ =\frac{-9}{8} $
View full question & answer→Question 193 Marks
The sum of two rational numbers is $\frac{11}{24}$. If one of them is $\frac{3}{8}$, fine the other.
Answer
$\begin{aligned} & \because \text { Sum of two rational number }=\frac{11}{24} \\ & \text { one of them }=\frac{3}{8} \\ & \therefore \text { The other rational number }=\frac{11}{24}-\frac{3}{8} \\ & =\frac{11}{24}-\frac{3 \times 3}{8 \times 3}=\frac{11}{24}-\frac{9}{24} \\ & =\frac{11-9}{24}=\frac{2}{24}=\frac{1}{12}\end{aligned}$
View full question & answer→Question 203 Marks
Subtract: $\frac{5}{8}$ from $\frac{-5}{16}$
Answer
$\begin{aligned} & \frac{5}{8} \text { from } \frac{-5}{16} \\ & =\frac{-5}{16}-\left(\frac{5}{8}\right) \\ & =\frac{-5}{16}-\frac{5 \times 2}{8 \times 2}=\frac{-5}{16}-\frac{10}{16} \\ & =\frac{-5-10}{16}=\frac{-15}{16}\end{aligned}$
View full question & answer→Question 213 Marks
Subtract: -2 from $\frac{-3}{10}$
Answer
$\begin{aligned} & -2 \text { from } \frac{-3}{10} \\ & =\frac{-3}{10}-\left(\frac{-2}{1}\right) \\ & =\frac{-3}{10}+\frac{2}{1} \\ & =\frac{-3+2 \times 10}{10}=\frac{17}{10}\end{aligned}$
View full question & answer→Question 223 Marks
Subtract: $\frac{-7}{4}$ from -2
Answer
$\begin{aligned} & \frac{-7}{4} \text { from }-2 \\ & =\frac{-2}{1}-\left(\frac{-7}{4}\right) \\ & =\frac{-2 \times 4}{1 \times 4}+\frac{7}{4} \\ & =\frac{-8}{4}+\frac{7}{4} \\ & =\frac{-8+7}{4}=\frac{-1}{4}\end{aligned}$
View full question & answer→Question 233 Marks
Subtract: $\frac{-6}{25}$ from $\frac{-8}{5}$
Answer
$\begin{aligned} & -\frac{3}{10} \text { from } \frac{1}{5} \\ & =\frac{-8}{5}-\left(\frac{-6}{25}\right) \\ & =\frac{-8 \times 5}{5 \times 5}+\frac{6}{25} \\ & =\frac{-40}{25}+\frac{6}{25} \\ & =\frac{-40+6}{25}=\frac{-34}{25}\end{aligned}$
View full question & answer→Question 243 Marks
Subtract: $-\frac{3}{10}$ from $\frac{1}{5}$
Answer
$\begin{aligned} & -\frac{3}{10} \text { from } \frac{1}{5} \\ & =\frac{1}{5}-\left(-\frac{3}{10}\right) \\ & =\frac{1 \times 2}{5 \times 2}+\frac{3}{10} \\ & =\frac{2}{10}+\frac{3}{10}=\frac{2+3}{10}=\frac{5}{10}\end{aligned}$
View full question & answer→Question 253 Marks
Evaluate: $\frac{5}{-24}+\frac{-1}{8}+\frac{3}{16}$
Answer
$\begin{aligned} & \frac{5}{-24}+\frac{-1}{8}+\frac{3}{16} \\ & =\frac{-5 \times 2}{24 \times 2}+\frac{-1 \times 6}{8 \times 6}+\frac{3 \times 3}{16 \times 3} \quad(\because \text { L.C.M. of } 8,16,24=48) \\ & =\frac{-10}{48}+\frac{-6}{48}+\frac{9}{48} \\ & =\frac{-10-6+9}{48} \\ & =\frac{-16+9}{48}=\frac{-7}{48}\end{aligned}$
View full question & answer→Question 263 Marks
Add: $\frac{-9}{-16}$ and $\frac{-11}{8}$
Answer$\frac{-9}{-16}$ and $\frac{-11}{8}=\frac{9}{16}+\frac{-11}{8}$
$ =\frac{9 \times 1}{16 \times 1}+\frac{-11 \times 2}{8 \times 2} $
$(\because$ L.C.M. of 16 and $8=16$ )
$ =\frac{9}{16}+\frac{-22}{16} $
$ =\frac{(9)+(-22)}{16}=\frac{9-22}{16}=\frac{-13}{16} $
View full question & answer→Question 273 Marks
Add: $\frac{13}{-16}$ and $\frac{-11}{24}$
Answer
$\begin{aligned} & \frac{13}{-16} \text { and } \frac{-11}{24}=\frac{-13}{16}+\frac{-11}{24} \\ & =\frac{-13 \times 3}{16 \times 3}+\frac{-11 \times 2}{24 \times 2} \\ & (\because \text { L.C.M. of } 16 \text { and } 24=48) \\ & =\frac{-39}{48}+\frac{-22}{48} \\ & =\frac{(-39)+(-22)}{48}=\frac{-39-22}{48}=\frac{-61}{48}\end{aligned}$
View full question & answer→Question 283 Marks
Add: $\frac{-9}{25}$ and $\frac{1}{-75}$
Answer
$\begin{aligned} & \frac{-9}{25} \text { and } \frac{1}{-75}=\frac{-9}{25}+\frac{-1}{75} \\ & =\frac{-9 \times 3}{25 \times 3}+\frac{-1 \times 1}{75 \times 1} \\ & (\because \text { L.C.M. of } 25 \text { and } 75=75) \\ & =\frac{-27}{75}+\frac{-1}{75} \\ & =\frac{(-27)+(-1)}{75}=\frac{-27-1}{75}=\frac{-28}{75}\end{aligned}$
View full question & answer→Question 293 Marks
Add: $\frac{1}{-18}$ and $\frac{5}{-27}$
Answer
$\begin{aligned} & \frac{1}{-18} \text { and } \frac{5}{-27}=\frac{-1}{18}+\frac{-5}{27} \\ & =\frac{-1 \times 3}{18 \times 3}+\frac{-5 \times 2}{27 \times 2} \\ & (\because \text { L.C.M. of } 18 \text { and } 27=54) \\ & =\frac{-3}{54}+\frac{-10}{54} \\ & =\frac{(-3)+(-10)}{54}=\frac{-3-10}{54}=\frac{-13}{54}\end{aligned}$
View full question & answer→Question 303 Marks
Add: $\frac{-7}{24}$ and $\frac{-5}{48}$
Answer $\frac{-7}{24}$ and $\frac{-5}{48}$
$ =\frac{-7 \times 2}{24 \times 2}+\frac{-5 \times 1}{48 \times 1} $
$(\because$ L.C.M. of 24 and $48=48)$
$ =\frac{-14}{48}+\frac{-5}{48} $
$=\frac{(-14)+(-5)}{48}=\frac{-14-5}{48}=\frac{-19}{48}$
View full question & answer→Question 313 Marks
Add: $\frac{-5}{9}$ and $\frac{7}{18} \mathrm{}$
Answer
$\begin{aligned} & \frac{-5}{9} \text { and } \frac{7}{18}=\frac{-5}{9}+\frac{7}{18} \\ & =\frac{-5 \times 2}{9 \times 2}+\frac{7 \times 1}{18 \times 1} \\ & (\because \text { L.C.M. of } 9 \text { and } 18=18) \\ & =\frac{-10}{18}+\frac{7}{18} \\ & =\frac{-10+7}{18}=\frac{-3}{18}\end{aligned}$
View full question & answer→Question 323 Marks
Add: -3 and $\frac{2}{3}$
Answer
$\begin{aligned} & -3 \text { and } \frac{2}{3}=\frac{-3}{1}+\frac{2}{3} \\ & =\frac{-3 \times 3}{1 \times 3}+\frac{2 \times 1}{3 \times 1} \\ & (\because \text { L.C.M. of } 1 \text { and } 3=3) \\ & =\frac{-9}{3}+\frac{2}{3} \\ & =\frac{-9+2}{3}=\frac{-7}{3}\end{aligned}$
View full question & answer→Question 333 Marks
Add: $\frac{-5}{6}$ and $\frac{4}{9}$
Answer
$\begin{aligned} & \frac{-5}{6} \text { and } \frac{4}{9}=\frac{-5}{6}+\frac{4}{9} \\ & =\frac{-5 \times 3}{6 \times 3}+\frac{4 \times 2}{9 \times 2} \\ & (\because \text { L.C.M. of } 6 \text { and } 9=18) \\ & =\frac{-15}{18}+\frac{8}{18} \\ & =\frac{-15+8}{18} \\ & =\frac{-7}{18}\end{aligned}$
View full question & answer→Question 343 Marks
The sum of two numbers is $-\frac{6}{5}$. If one of them is -2 , find the other.
Answer
$\begin{aligned} & \because \text { Sum of two rational number }=-\frac{6}{5} \\ & \text { and one of them }=-2 \\ & \therefore \text { Other rational number }=-\frac{6}{5}-\left(-\frac{2}{1}\right) \\ & =\frac{-6+2 \times 5}{5}=\frac{-6+10}{5}=\frac{4}{5}\end{aligned}$
View full question & answer→Question 353 Marks
What should be subtracted from $\frac{-4}{5}$ to get 1 ?
AnswerLet the required rational number be $x$
Other number $=\frac{-3}{5}$
Difference of two number $=1$
According to question,
$ \begin{aligned} & \therefore \frac{-4}{5}-\mathrm{x}=1 \\ & \Rightarrow \frac{-4}{5}-1=\mathrm{x} \\ & \Rightarrow \mathrm{x}=\frac{-4-1 \times 5}{5}=\frac{-9}{5} \end{aligned} $
View full question & answer→Question 363 Marks
What should be added to $\frac{-3}{5}$ to get $2 ?$
AnswerLet the required rational number be $x$
Other number $=\frac{-3}{5}$
Sum of two number $=2$
According to question,
$ \begin{aligned} & \frac{-3}{5}+\mathrm{x}=2 \\ & \Rightarrow \mathrm{x}=2+\frac{3}{5} \\ & =\frac{2 \times 5+3}{5}=\frac{10+3}{5}=\frac{13}{5} \end{aligned} $
View full question & answer→Question 373 Marks
Compare: $\frac{5}{-9}$ and $\frac{-5}{-9}$
Answer
$\begin{aligned} & \frac{5}{-9} \text { and } \frac{-5}{-9} \\ & 5 \times-9 \text { and }-5 \times-9 \\ & \left(\therefore \frac{a}{b} \text { and } \frac{c}{d} \Rightarrow \mathrm{a} \times \mathrm{d} \text { and } \mathrm{b} \times \mathrm{c}\right) \\ & -45<45 \quad(\because \mathrm{a} \times \mathrm{d}<\mathrm{b} \times \mathrm{c}) \\ & \therefore \frac{5}{-9}<\frac{-5}{-9}\end{aligned}$
View full question & answer→Question 383 Marks
Find three rational numbers equivalent to $-\frac{5}{9}$
Answer$ \frac{-5}{9}=\frac{-5 \times 2}{9 \times 2}=\frac{-10}{18}, \frac{-5 \times 3}{9 \times 3}=\frac{-15}{27} $
and $\frac{-5 \times 4}{9 \times 4}=\frac{-20}{36}$
Hence $\frac{-10}{18}, \frac{-15}{27}$ and $\frac{-20}{36}$ are rational numbers equivalent to given rational number $\frac{-5}{9}$.
View full question & answer→Question 393 Marks
Separate positive and negative rational numbers from the following:
$ \frac{-3}{5}, \frac{3}{-5}, \frac{-3}{-5}, \frac{3}{5}, 0, \frac{-13}{-3}, \frac{15}{-8}, \frac{-15}{8} $
AnswerPositive rational numbers are $\frac{-3}{-5}=\frac{3}{5}$ (as both or negative)
$\frac{-13}{-3}=\frac{13}{3}$ (as both are negative)
Negative rational numbers $=\frac{-3}{5}, \frac{3}{-5}, \frac{15}{-8}$ and $\frac{-15}{8}$
0 is neither positive nor negative integer.
View full question & answer→Question 403 Marks
Express the following rational numbers to the lowest terms: $\frac{14}{-56}$
Answer$\frac{14}{-56}$
$14) \overline{56}(4$
56
X
(Dividing by 14 , H.C.F. of 14 and -56 )
$\Rightarrow \frac{14 \div 14}{-56 \div 14}=\frac{1}{-4}=-\frac{1}{4} $
View full question & answer→Question 413 Marks
Express the following rational numbers to the lowest terms: $\frac{-48}{-72}$
Answer$\frac{-48}{-72}$
$\begin{array}{c}48) \overline{72}(1 \\ 48 \\ 24) \overline{48}(2\end{array}$
48
X
(Dividing by 24, H.C.F. of -48 and -72 )
$\Rightarrow \frac{-48 \div 24}{-72 \div 24}=\frac{-2}{-3}=\frac{2}{3}$
View full question & answer→Question 423 Marks
Express the following rational numbers to the lowest terms: $\frac{-120}{144}$
Answer$\frac{-120}{144}$
$120) \overline{144}(1$
$120$
$24) \overline{120}(5$
$120$
$X$
$($Dividing by $24, \text{H.C.F.}$ of $-120$ and $144)$
$ \Rightarrow \frac{-120 \div 24}{144 \div 24}=\frac{-5}{6} $
View full question & answer→Question 433 Marks
Express the following rational number to the lowest term: $\frac{12}{15}$
Answer$ \frac{12}{15} $
12) $\overline{15}(1$
12
3) $\overline{12}(4$
12
X
(Dividing by 3, H.C.F. of 12 and 15)
$ \Rightarrow \frac{12 \div 3}{15 \div 3}=\frac{4}{5} $
View full question & answer→Question 443 Marks
Find $x$, such that: $\frac{-27}{x}=9$
Answer
$\begin{aligned} & \frac{-27}{\mathrm{x}}=9 \\ & \Rightarrow \frac{-27}{\mathrm{x}}=\frac{9}{1} \\ & \Rightarrow \frac{-27}{\mathrm{x}}=\frac{9 \times(-3)}{1 \times(-3)} \\ & \Rightarrow \frac{-27}{\mathrm{x}}=\frac{-27}{-3} \\ & \Rightarrow \mathrm{x}=-3\end{aligned}$
View full question & answer→Question 453 Marks
Find $x$, such that: $\frac{36}{x}=3$
Answer
$\begin{aligned} & \frac{36}{\mathrm{x}}=3 \\ & \Rightarrow \frac{36}{\mathrm{x}}=\frac{3}{1} \\ & \Rightarrow \frac{36}{\mathrm{x}}=\frac{3 \times 12}{1 \times 12} \\ & \Rightarrow \frac{36}{\mathrm{x}}=\frac{36}{12} \\ & \Rightarrow \mathrm{x}=12\end{aligned}$
View full question & answer→Question 463 Marks
Find $x$, such that: $\frac{-48}{x}=6$
Answer
$\begin{aligned} & \frac{-48}{\mathrm{x}}=6 \\ & \Rightarrow \frac{-48}{\mathrm{x}}=\frac{6}{1} \\ & \Rightarrow \frac{-48}{\mathrm{x}}=\frac{6 \times-8}{1 \times-8} \\ & \Rightarrow \frac{-48}{\mathrm{x}}=\frac{-48}{-8} \\ & \Rightarrow \mathrm{x}=-8\end{aligned}$
View full question & answer→Question 473 Marks
Find $x$, such that: $\frac{3}{7}=\frac{\mathrm{x}}{-35}$
Answer
$\begin{aligned} & \frac{7}{-4}=\frac{x}{8} \\ & \Rightarrow \frac{3 \times-5}{7 \times-5}=\frac{\mathrm{x}}{-35} \\ & \Rightarrow \frac{-15}{-35}=\frac{\mathrm{x}}{-35} \\ & \Rightarrow x=-15\end{aligned}$
View full question & answer→Question 483 Marks
Find $x$, such that: $\frac{7}{-4}=\frac{x}{8}$
Answer
$ \begin{aligned} & \frac{7}{-4}=\frac{x}{8} \\ & -4 x=7 \times 8 \\ & x=\frac{7 \times 8}{-4}=-7 \times 2=-14 \\ & x=-14 \end{aligned} $
OR
$ \begin{aligned} & \Rightarrow \frac{-7 \times 2}{4 \times 2}=\frac{x}{8} \\ & \Rightarrow-\frac{14}{8}=\frac{x}{8} \\ & x=-14 \end{aligned} $
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