Question
Find $(x + y) ÷ (x − y)$, if $\text{x}=\frac{1}{4},\text{y}=\frac{3}{2}$

Answer

$\text{x}=\frac{1}{4},\text{y}=\frac{3}{2}$
$\text{x}+\text{y}=\frac{1}{4}+\frac{3}{2}$
$=\frac{1+6}{4}=\frac{7}{4}$
$\text{x}-\text{y}=\frac{1}{4}-\frac{3}{2}$
$=\frac{1-6}{4}=\frac{-5}{4}$
$\therefore(\text{x}+\text{y})\div(\text{x}-\text{y})=\frac{7}{4}\div\Big(\frac{-5}{4}\Big)$
$=\frac{7}{4}\times\frac{4}{-5}=\frac{7}{-5}$
$=\frac{7\times(-1)}{-5\times(-1)}=\frac{-7}{5}$

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