MCQ
Finely divided iron combines with $CO$ to give
- ✓$Fe{(CO)_5}$
- B$F{e_2}{(CO)_9}$
- C$F{e_3}{(CO)_{12}}$
- D$Fe{(CO)_6}$
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(At nos. : $L a=57, C e=58, E u=63$ and $Y b=70$ )
$\operatorname{cis}-\left[\mathrm{Cr}(\mathrm{ox})_2 \mathrm{Cl}_2\right]^{3-},\left[\mathrm{Co}(\mathrm{en})_3\right]^{3+}$
$\operatorname{cis}-\left[\mathrm{Pt}(\mathrm{en})_2 \mathrm{Cl}_2\right]^{2+}, \text { cis }-\left[\mathrm{Co}(\mathrm{en})_2 \mathrm{Cl}_2\right]^{+}$
$\text {trans }-\left[\mathrm{Pt}(\mathrm{en})_2 \mathrm{Cl}_2\right]^{2+}, \text { trans }-\left[\mathrm{Cr}(\mathrm{ox})_2 \mathrm{Cl}_2\right]^{3-}$
$\text { A } \quad\quad\quad\quad\quad \text { B } \quad\quad\quad\text { C } \quad\quad\quad\quad\text { D }$
$1 \times 10^{-4} \quad 2 \times 10^{-4} \quad 0.1 \times 10^{-4} \quad 0.2 \times 10^{-4}$
(Where $E$ is the electromotive force)
Which of the above half cells would be preferred to be used as reference electrode?