Five capacitors together with their capacitances are shown in the adjoining figure. The potential difference between the points $A$ and $B$ is $60\, volt.$ The equivalent capacitance between the point $A$ and $B$ and charge on capacitor $5\,\mu F$ will be respectively :-
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$\frac{1}{C_{e q}}=\frac{1}{8}+\frac{1}{24}+\frac{1}{12} \Rightarrow C_{e q}=4\, \mu F$

$\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=60 \mathrm{\,V}$

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