Five conducting parallel plates having area $A$ and separation between them $d$, are placed as shown in the figure. Plate number $2$ and $4$ are connected wire and between point $A$ and $B$, a cell of emf $E$ is connected. The charge flown through the cell is
Diffcult
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Net capacitance
$=\frac{\left(\frac{2 \in 0 A}{d}\right)\left(\frac{\in 0 A}{d}\right)}{\frac{2 \in_{o} A}{d}}$
$=\frac{2}{3} \frac{\in_{0} A}{d}$
Charge flown $=C E$
$=\frac{2}{3} \frac{\in_{0} A}{d} E$
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