A $500 \,\mu F$ capacitor is charged at a steady rate of $100\, \mu C/sec$. The potential difference across the capacitor will be $10\, V$ after an interval of.....$sec$
Medium
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(d) Charge required to reach the capacitor upto $10\, V$ is
$Q = 500 \times {10^{ - 6}} \times 10 = 5 \times {10^{ - 3}}\,C$
Now required time $ = \frac{{5 \times {{10}^{ - 3}}}}{{100 \times {{10}^{ - 6}}}}$ $= 50\, sec$
$Q = 500 \times {10^{ - 6}} \times 10 = 5 \times {10^{ - 3}}\,C$
Now required time $ = \frac{{5 \times {{10}^{ - 3}}}}{{100 \times {{10}^{ - 6}}}}$ $= 50\, sec$
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