MCQ
Five identical rods are joined as shown in figure. Point $A$ and $C$ are maintained at temperature $120^o C$ and $20^o C$ respectively. The temperature of junction $B$ will be....... $^oC$


- A$100$
- B$80$
- ✓$70$
- D$0$

(Heat current)$_{AC} =$ (Heat current)$_{AB}$
$\frac{{(120 - 20)}}{R} = \frac{{(120 - \theta )}}{R}$
==> $\theta = 70^\circ C$
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[Boltzmann’s constant ${k_B} = 1.38 \times {10^{ - 23}}J/K]$