Question
फलन $\sin ^{-1} 2 x$ का प्रान्त है-

Answer

(C) $\left[-\frac{1}{2}, \frac{1}{2}\right]$
$\sin ^{-1} 2 x$ परिभाषित होगा यदि - $1 \leq 2 x \leq 1 \Rightarrow-\frac{1}{2} \leq x$$\leq \frac{1}{2} \Rightarrow x \in\left[-\frac{1}{2}, \frac{1}{2}\right]$
अतः विकल्प (C) सही है।

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