MCQ
Fluorine does not form positive oxidation states because
- ✓It is most electronegative element
- BIt forms only anions in ionic compounds
- CIt cannot form multiple bonding
- DIt shows non-bonded electron pair repulsion due to small size
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$[Figure]$ $\longrightarrow \,\,A\,\xrightarrow{{{C_6}{H_5}N{H_2}}}B$
The equilibrium constant for the reaction is $K_{p}=4$, At equilibrium, the partial pressure of $\mathrm{O}_{2}$ is $....\,atm.$ (Round off to the nearest integer).
