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$Al_{(S)}+3Ag^+_{(aq)}\,(0.10\, M) \to Al^{+3}_{(aq)}\, (0.30\, M)+3Ag_{(S)}$,
the measured voltage $(E_{cell})$ is $1.50\, volt$. Calculate $E_{cell}^o$ ........... $\mathrm{volt}$
Given : $\frac{{2.303\,RT}}{F} = 0.06\,;\,\log \,3 = 0.48$
| Item $I$ | Item $II$ |
| $A$ Allosteric effect | $P$ Molecule binding to the active site of enzyme |
| $B$ Competitive inhibitor | $Q$ Molecule crucial for communication in the body |
| $C$ Receptor | $R$ Molecule binding to a site other than the active site of enzyme |
| $D$ Poison | $S$ Molecule binding to the enzyme covalently |
take place in two steps :
$(a)$ $Br^{-} + H^{+} + H_2O_2 \xrightarrow{{slow}} HOBr + H_2O$
$(b)$ $HOBr + Br^{-} + H^{+} \xrightarrow{{fast}} H_2O + Br_2$
The order of the reaction is
