For a certain organ pipe three successive resonance frequencies are observed at $425 \,\,Hz$, $595\,\, Hz$ and $765\,\, Hz$ respectively. If the speed of sound in air is $340 \,\,m/s$, then the length of the pipe is .... $m$
Diffcult
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since frequencies are in odd number ratio, the pipe has to be a closed pipe.
Ratio of $3$ frequencies $=425: 595: 765$
$=5: 7: 9$
So fundamental frequency $=f=\frac{425}{5}=85 H z$
For fundamental frequency
$l=\frac{v}{4 f}=\frac{340}{4 \times 85}=1 m$
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