MCQ
For a frequency distribution, mean, median and mode are connected by the relation:
- AMode = 3 Mean – 2 Median.
- BMode = 2 Median – 3 Mean.
- ✓Mode = 3 Median – 2 Mean.
- DMode = 3 Median + 2 Mean.
✓
Answer
Correct option: C.
Mode = 3 Median – 2 Mean.
The relation between mean, median and mode is:
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
$\frac{1}{\sqrt{2}}$ is :
→→
Mark the correct alternative in the following : The common difference of an $A.P.,$ the sum of whose $n$ terms is $S_n$, is
→The line segment joining points $(-3,-4)$, and $(1,-2)$ is divided by $y$-axis in the ratio
→In the given figure, the sides $AB, BC$ and $CA$ of triangle $\text{ABC},$ touch a circle at $P, Q$ and $R$ respectively. If $PA = 4\ cm, BP = 3\ cm$ and $AC = 11\ cm,$ then length of $BC$ is :
→The circular ends of a bucket are of radii $35 \ cm$ and $14 \ cm$ and the height of the bucket is $40 \ cm .$ Its volume is
→In Fig, $\triangle A B C \sim \triangle Q P R$. If $A C=6 cm, B C=5 cm, Q R=3 cm$ and $P R=x cm$, then the value of $x$ is
→What values of $x$ will make $D E \| A B$ in the figure?
→$\Bigg\{\frac{\big(\sin^222^\circ+\sin^268^\circ\big)}{\big(\cos^222^\circ+\cos^268^\circ\big)}+\sin^263^\circ\\+\cos63^\circ\sin27^\circ\Bigg\}=?$
→A right circular cylinder of radius r and height h (h > 2r) just encloses a sphere of diameter: