$\Rightarrow \,\,\frac{{{v_1}}}{{{v_2}}} = \sqrt {\frac{{{T_1}}}{{{T_2}}}} = \sqrt {\frac{{200}}{{800}}} = \frac{1}{2}$
$\Rightarrow$ ${v_2} = 2{v_1}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Statement $-1$ : No change in the temperature of the gas takes place when ideal gas expands in vacuum. However, the temperature of real gas goes down (cooling) when it expands in vacuum
Statement $-2$ : The internal energy of an ideal gas is only kinetic. The internal energy of a real gas is kinetic as well as potential
$V_x=V_0 \sin \omega t$ $V_y=V_0 \sin \left(\omega t+\frac{2 \pi}{3}\right) \text { and }$ $V_z=V_0 \sin \left(\omega t+\frac{4 \pi}{3}\right)$
An ideal voltmeter is configured to read rms value of the potential difference between its terminals. It is connected between points $\mathrm{X}$ and $\mathrm{Y}$ and then between $\mathrm{Y}$ and $\mathrm{Z}$. The reading(s) of the voltmeter will be
$[A]$ $\mathrm{V}_{\mathrm{XY}}^{\mathrm{mms}}=\mathrm{V}_0 \sqrt{\frac{3}{2}}$
$[B]$ $\mathrm{V}_{\mathrm{YZ}}^{\mathrm{mms}}=\mathrm{V}_0 \sqrt{\frac{1}{2}}$
$[C]$ $\mathrm{V}_{\mathrm{XY}}^{\mathrm{mms}}=\mathrm{V}_0$
$[D]$ independent of the choice of the two terminals