For a given triode $\mu=20$. The load resistance is $1.5$ times the anode resistance. The maximum gain will be
A$16$
B$12$
C$10$
D
None of the above
[CPMT 1992]
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B$12$
$ \text { Voltage gain } A_v=\frac{\mu}{1+\frac{r_p}{R_L}}$
$ \because R_L=1.5 r_p \Rightarrow A_v=\frac{\mu}{1+\frac{r_p}{1.5 r_p}}=\frac{3}{5} \mu=\frac{3}{5} \times 20=12 .$
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Before the saturation state of a diode at the plate voltages of $400 V$ and $200 V$ respectively the currents are $i$ and $i$ respectively. The ratio $i / i$ will be