Question
For a G.P.$a=2, r=-\frac{2}{3}$, find $S_6$

Answer

$a=2, r=-\frac{2}{3}$
$S_n=\frac{a\left(1-r^n\right)}{1-r}, \text { for } r<1$
$S_6=\frac{2\left[1-\left(-\frac{2}{3}\right)^6\right]}{1-\left(-\frac{2}{3}\right)}$
$ =\frac{2\left[1-\left(\frac{2}{3}\right)^6\right]}{\frac{5}{3}} $
$ =\frac{6}{5}\left[\frac{729-64}{3^6}\right] $
$=\frac{6}{5}\left[\frac{665}{729}\right]$
$S _6  =\frac{266}{243}$

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