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STD 11 - 13. oscillations — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 13. oscillations4 Marks
MCQ
For a particle executing $S.H.M.,\, x =$ displacement from equilibrium position, $v =$ velocity at any instant and $a =$ acceleration at any instant, then
  • A
    $a-v$ graph is an ellipse
  • B
    $v-x$ graph is an ellipse
  • C
    $a-x$ graph is a straight line
  • ✓
    all of the above
✓

Answer

Correct option: D.
all of the above
d
$x=A \sin (\omega t+b)$

$\boldsymbol{v}=A \omega \cos (\omega t+b)$

$a=-A \omega^{2} \sin (\omega t+b)$

so $x^{2}+v^{2} / \omega^{2}=A^{2} \ldots$ ellipse

$\boldsymbol{a}=-\boldsymbol{\omega}^{2} \boldsymbol{x} \ldots \ldots$ straight line

$v^{2}+a^{2} / \omega^{2}=A^{2} \omega^{2} \ldots . .$ ellipse

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