MCQ
For a particle performing linear S.H.M., its average speed over one oscillation is ( $a=$ amplitude of S.H.M., $n=$ frequency of oscillation)
- A$2 a n$
- ✓$4 a n$
- C$6 a n$
- D$8 a n$
✓
Answer
Correct option: B.
$4 a n$
(b) : Distance travelled in one oscillation is $4 a$ and time period is $T$.
$
\text { Velocity }=\frac{4 a}{T}=4 a n \quad\left[\because n=\frac{1}{T}\right]
$
$
\text { Velocity }=\frac{4 a}{T}=4 a n \quad\left[\because n=\frac{1}{T}\right]
$
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