MCQ
For a reversible spontaneous change $\Delta S$ is
  • A
    $\frac{{\Delta E}}{T}$
  • B
    $\frac{{P\,\Delta V}}{T}$
  • $\frac{q}{T}$
  • D
    $RT\, log\, K$

Answer

Correct option: C.
$\frac{q}{T}$
c
$ds =\frac{ dq \cdot rev }{ T }$

$\Delta s =\frac{\int dq \cdot rev }{ T }$

$\int dq \cdot$ rev.q (for rev. provess)

$\Delta s =\frac{ q }{ T }$

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