MCQ
For a rigid diatomic molecule, universal gas constant $R=n C_p$ where $C_p$ is the molar specific heat at constant pressure and $n$ is a number. Hence $n$ is equal to
- A0.2257
- B0.4
- ✓0.2857
- D0.3557
✓
Answer
Correct option: C.
0.2857
(c) : For a rigid diatomic molecule
$
\begin{aligned}
& \frac{C_P}{C_V}=\frac{7}{5} \\
& C_V=\frac{5}{7} C_P \\
& C_P-C_V=R \\
& C_P-\frac{5}{7} C_P=n C_P
\end{aligned}
$
$\frac{2}{7} C_p=n C_p \Rightarrow n=\frac{2}{7}=0.2857$
$
\begin{aligned}
& \frac{C_P}{C_V}=\frac{7}{5} \\
& C_V=\frac{5}{7} C_P \\
& C_P-C_V=R \\
& C_P-\frac{5}{7} C_P=n C_P
\end{aligned}
$
$\frac{2}{7} C_p=n C_p \Rightarrow n=\frac{2}{7}=0.2857$
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