For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is $1\,kg$, the angular frequency is $\omega_1$. When the mass block is $2\,kg$ the angular frequency is $\omega_2$. The ratio $\omega_2 / \omega_1$ is
JEE MAIN 2023, Easy
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$\omega=\sqrt{\frac{ k }{ m }}$
$\frac{\omega_2}{\omega_1}=\sqrt{\frac{ m _1}{ m _2}}=\sqrt{\frac{1}{2}}$
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